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5(x-5)=4(5+x)
We move all terms to the left:
5(x-5)-(4(5+x))=0
We add all the numbers together, and all the variables
5(x-5)-(4(x+5))=0
We multiply parentheses
5x-(4(x+5))-25=0
We calculate terms in parentheses: -(4(x+5)), so:We get rid of parentheses
4(x+5)
We multiply parentheses
4x+20
Back to the equation:
-(4x+20)
5x-4x-20-25=0
We add all the numbers together, and all the variables
x-45=0
We move all terms containing x to the left, all other terms to the right
x=45
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