5(x-4)=6(5+2x)-7

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Solution for 5(x-4)=6(5+2x)-7 equation: 



5(x-4)=6(5+2x)-7

We move all terms to the left:

5(x-4)-(6(5+2x)-7)=0

We add all the numbers together, and all the variables

5(x-4)-(6(2x+5)-7)=0

We multiply parentheses

5x-(6(2x+5)-7)-20=0



We calculate terms in parentheses: -(6(2x+5)-7), so:

6(2x+5)-7

We multiply parentheses

12x+30-7

We add all the numbers together, and all the variables

12x+23

Back to the equation:

-(12x+23)



We get rid of parentheses

5x-12x-23-20=0

We add all the numbers together, and all the variables

-7x-43=0

We move all terms containing x to the left, all other terms to the right

-7x=43

x=43/-7

x=-6+1/7

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