5(x-4)=2(-x+11)

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Solution for 5(x-4)=2(-x+11) equation: 



5(x-4)=2(-x+11)

We move all terms to the left:

5(x-4)-(2(-x+11))=0

We add all the numbers together, and all the variables

5(x-4)-(2(-1x+11))=0

We multiply parentheses

5x-(2(-1x+11))-20=0



We calculate terms in parentheses: -(2(-1x+11)), so:

2(-1x+11)

We multiply parentheses

-2x+22

Back to the equation:

-(-2x+22)



We get rid of parentheses

5x+2x-22-20=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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