5(x-4)-3(x+2)=0

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Solution for 5(x-4)-3(x+2)=0 equation:



5(x-4)-3(x+2)=0
We multiply parentheses
5x-3x-20-6=0
We add all the numbers together, and all the variables
2x-26=0
We move all terms containing x to the left, all other terms to the right
2x=26
x=26/2
x=13

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