5(x-4)-3(x+2)=(x-8)

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Solution for 5(x-4)-3(x+2)=(x-8) equation:



5(x-4)-3(x+2)=(x-8)
We move all terms to the left:
5(x-4)-3(x+2)-((x-8))=0
We multiply parentheses
5x-3x-((x-8))-20-6=0
We calculate terms in parentheses: -((x-8)), so:
(x-8)
We get rid of parentheses
x-8
Back to the equation:
-(x-8)
We add all the numbers together, and all the variables
2x-(x-8)-26=0
We get rid of parentheses
2x-x+8-26=0
We add all the numbers together, and all the variables
x-18=0
We move all terms containing x to the left, all other terms to the right
x=18

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