5(x-4)-1=6(x+2/3)

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Solution for 5(x-4)-1=6(x+2/3) equation:



5(x-4)-1=6(x+2/3)
We move all terms to the left:
5(x-4)-1-(6(x+2/3))=0
We add all the numbers together, and all the variables
5(x-4)-(6(+x+2/3))-1=0
We multiply parentheses
5x-(6(+x+2/3))-20-1=0
We multiply all the terms by the denominator
5x*3))-(6(+x+2-20*3))-1*3))=0
We add all the numbers together, and all the variables
5x*3))-(6(x-58))-1*3))=0
We add all the numbers together, and all the variables
5x*3))-(6(x=0
Wy multiply elements
15x^2=0
a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{30}=0$

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