5(x-4)+x=3(x-6)+2

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Solution for 5(x-4)+x=3(x-6)+2 equation: 



5(x-4)+x=3(x-6)+2

We move all terms to the left:

5(x-4)+x-(3(x-6)+2)=0

We add all the numbers together, and all the variables

x+5(x-4)-(3(x-6)+2)=0

We multiply parentheses

x+5x-(3(x-6)+2)-20=0



We calculate terms in parentheses: -(3(x-6)+2), so:

3(x-6)+2

We multiply parentheses

3x-18+2

We add all the numbers together, and all the variables

3x-16

Back to the equation:

-(3x-16)



We add all the numbers together, and all the variables

6x-(3x-16)-20=0

We get rid of parentheses

6x-3x+16-20=0

We add all the numbers together, and all the variables

3x-4=0

We move all terms containing x to the left, all other terms to the right

3x=4

x=4/3

x=1+1/3

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