5(x-4)+8(2x+2)=6(x+1)+5(x+10

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Solution for 5(x-4)+8(2x+2)=6(x+1)+5(x+10 equation: 



5(x-4)+8(2x+2)=6(x+1)+5(x+10

We move all terms to the left:

5(x-4)+8(2x+2)-(6(x+1)+5(x+10)=0

We multiply parentheses

5x+16x-(6(x+1)+5(x+10)-20+16=0

We add all the numbers together, and all the variables

21x-(6(x+1)+5(x+10)-20+16=0

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