5(x-4)+6x-(7x+3)=1

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Solution for 5(x-4)+6x-(7x+3)=1 equation: 



5(x-4)+6x-(7x+3)=1

We move all terms to the left:

5(x-4)+6x-(7x+3)-(1)=0

We add all the numbers together, and all the variables

6x+5(x-4)-(7x+3)-1=0

We multiply parentheses

6x+5x-(7x+3)-20-1=0

We get rid of parentheses

6x+5x-7x-3-20-1=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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