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5(x-4)+6=2(x+3)+x
We move all terms to the left:
5(x-4)+6-(2(x+3)+x)=0
We multiply parentheses
5x-(2(x+3)+x)-20+6=0
We calculate terms in parentheses: -(2(x+3)+x), so:We add all the numbers together, and all the variables
2(x+3)+x
We add all the numbers together, and all the variables
x+2(x+3)
We multiply parentheses
x+2x+6
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
5x-(3x+6)-14=0
We get rid of parentheses
5x-3x-6-14=0
We add all the numbers together, and all the variables
2x-20=0
We move all terms containing x to the left, all other terms to the right
2x=20
x=20/2
x=10
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