5(x-4)+4=2x+3(x+2)-22

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Solution for 5(x-4)+4=2x+3(x+2)-22 equation:


Simplifying
5(x + -4) + 4 = 2x + 3(x + 2) + -22

Reorder the terms:
5(-4 + x) + 4 = 2x + 3(x + 2) + -22
(-4 * 5 + x * 5) + 4 = 2x + 3(x + 2) + -22
(-20 + 5x) + 4 = 2x + 3(x + 2) + -22

Reorder the terms:
-20 + 4 + 5x = 2x + 3(x + 2) + -22

Combine like terms: -20 + 4 = -16
-16 + 5x = 2x + 3(x + 2) + -22

Reorder the terms:
-16 + 5x = 2x + 3(2 + x) + -22
-16 + 5x = 2x + (2 * 3 + x * 3) + -22
-16 + 5x = 2x + (6 + 3x) + -22

Reorder the terms:
-16 + 5x = 6 + -22 + 2x + 3x

Combine like terms: 6 + -22 = -16
-16 + 5x = -16 + 2x + 3x

Combine like terms: 2x + 3x = 5x
-16 + 5x = -16 + 5x

Add '16' to each side of the equation.
-16 + 16 + 5x = -16 + 16 + 5x

Combine like terms: -16 + 16 = 0
0 + 5x = -16 + 16 + 5x
5x = -16 + 16 + 5x

Combine like terms: -16 + 16 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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