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5(x-4)+2x=-4(x-5)+11x
We move all terms to the left:
5(x-4)+2x-(-4(x-5)+11x)=0
We add all the numbers together, and all the variables
2x+5(x-4)-(-4(x-5)+11x)=0
We multiply parentheses
2x+5x-(-4(x-5)+11x)-20=0
We calculate terms in parentheses: -(-4(x-5)+11x), so:We add all the numbers together, and all the variables
-4(x-5)+11x
We add all the numbers together, and all the variables
11x-4(x-5)
We multiply parentheses
11x-4x+20
We add all the numbers together, and all the variables
7x+20
Back to the equation:
-(7x+20)
7x-(7x+20)-20=0
We get rid of parentheses
7x-7x-20-20=0
We add all the numbers together, and all the variables
-40!=0
There is no solution for this equation
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