5(x-4)+15=-10(x-1)+6

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Solution for 5(x-4)+15=-10(x-1)+6 equation: 



5(x-4)+15=-10(x-1)+6

We move all terms to the left:

5(x-4)+15-(-10(x-1)+6)=0

We multiply parentheses

5x-(-10(x-1)+6)-20+15=0



We calculate terms in parentheses: -(-10(x-1)+6), so:

-10(x-1)+6

We multiply parentheses

-10x+10+6

We add all the numbers together, and all the variables

-10x+16

Back to the equation:

-(-10x+16)



We add all the numbers together, and all the variables

5x-(-10x+16)-5=0

We get rid of parentheses

5x+10x-16-5=0

We add all the numbers together, and all the variables

15x-21=0

We move all terms containing x to the left, all other terms to the right

15x=21

x=21/15

x=1+2/5

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