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5(x-3)=4(2-x)
We move all terms to the left:
5(x-3)-(4(2-x))=0
We add all the numbers together, and all the variables
5(x-3)-(4(-1x+2))=0
We multiply parentheses
5x-(4(-1x+2))-15=0
We calculate terms in parentheses: -(4(-1x+2)), so:We get rid of parentheses
4(-1x+2)
We multiply parentheses
-4x+8
Back to the equation:
-(-4x+8)
5x+4x-8-15=0
We add all the numbers together, and all the variables
9x-23=0
We move all terms containing x to the left, all other terms to the right
9x=23
x=23/9
x=2+5/9
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