5(x-3)-7(6-x)+29=50+3(8-x)

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Solution for 5(x-3)-7(6-x)+29=50+3(8-x) equation: 



5(x-3)-7(6-x)+29=50+3(8-x)

We move all terms to the left:

5(x-3)-7(6-x)+29-(50+3(8-x))=0

We add all the numbers together, and all the variables

5(x-3)-7(-1x+6)-(50+3(-1x+8))+29=0

We multiply parentheses

5x+7x-(50+3(-1x+8))-15-42+29=0



We calculate terms in parentheses: -(50+3(-1x+8)), so:

50+3(-1x+8)

determiningTheFunctionDomain
3(-1x+8)+50

We multiply parentheses

-3x+24+50

We add all the numbers together, and all the variables

-3x+74

Back to the equation:

-(-3x+74)



We add all the numbers together, and all the variables

12x-(-3x+74)-28=0

We get rid of parentheses

12x+3x-74-28=0

We add all the numbers together, and all the variables

15x-102=0

We move all terms containing x to the left, all other terms to the right

15x=102

x=102/15

x=6+4/5

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