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5(x-3)-4=-2(x+3)+1
We move all terms to the left:
5(x-3)-4-(-2(x+3)+1)=0
We multiply parentheses
5x-(-2(x+3)+1)-15-4=0
We calculate terms in parentheses: -(-2(x+3)+1), so:We add all the numbers together, and all the variables
-2(x+3)+1
We multiply parentheses
-2x-6+1
We add all the numbers together, and all the variables
-2x-5
Back to the equation:
-(-2x-5)
5x-(-2x-5)-19=0
We get rid of parentheses
5x+2x+5-19=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2
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