5(x-3)-4(x-2)=0

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Solution for 5(x-3)-4(x-2)=0 equation:


Simplifying
5(x + -3) + -4(x + -2) = 0

Reorder the terms:
5(-3 + x) + -4(x + -2) = 0
(-3 * 5 + x * 5) + -4(x + -2) = 0
(-15 + 5x) + -4(x + -2) = 0

Reorder the terms:
-15 + 5x + -4(-2 + x) = 0
-15 + 5x + (-2 * -4 + x * -4) = 0
-15 + 5x + (8 + -4x) = 0

Reorder the terms:
-15 + 8 + 5x + -4x = 0

Combine like terms: -15 + 8 = -7
-7 + 5x + -4x = 0

Combine like terms: 5x + -4x = 1x
-7 + 1x = 0

Solving
-7 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 1x = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 1x = 0 + 7
1x = 0 + 7

Combine like terms: 0 + 7 = 7
1x = 7

Divide each side by '1'.
x = 7

Simplifying
x = 7

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