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5(x-3)-3(x+2)=9(2x+5)+14x-6
We move all terms to the left:
5(x-3)-3(x+2)-(9(2x+5)+14x-6)=0
We multiply parentheses
5x-3x-(9(2x+5)+14x-6)-15-6=0
We calculate terms in parentheses: -(9(2x+5)+14x-6), so:We add all the numbers together, and all the variables
9(2x+5)+14x-6
We add all the numbers together, and all the variables
14x+9(2x+5)-6
We multiply parentheses
14x+18x+45-6
We add all the numbers together, and all the variables
32x+39
Back to the equation:
-(32x+39)
2x-(32x+39)-21=0
We get rid of parentheses
2x-32x-39-21=0
We add all the numbers together, and all the variables
-30x-60=0
We move all terms containing x to the left, all other terms to the right
-30x=60
x=60/-30
x=-2
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