5(x-3)-2x=4+(x-5)

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Solution for 5(x-3)-2x=4+(x-5) equation: 



5(x-3)-2x=4+(x-5)

We move all terms to the left:

5(x-3)-2x-(4+(x-5))=0

We add all the numbers together, and all the variables

-2x+5(x-3)-(4+(x-5))=0

We multiply parentheses

-2x+5x-(4+(x-5))-15=0



We calculate terms in parentheses: -(4+(x-5)), so:

4+(x-5)

determiningTheFunctionDomain
(x-5)+4

We get rid of parentheses

x-5+4

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)



We add all the numbers together, and all the variables

3x-(x-1)-15=0

We get rid of parentheses

3x-x+1-15=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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