5(x-3)-2/5(5x-10)=-1/2(6-8x)=

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Solution for 5(x-3)-2/5(5x-10)=-1/2(6-8x)= equation: 



5(x-3)-2/5(5x-10)=-1/2(6-8x)=

We move all terms to the left:

5(x-3)-2/5(5x-10)-(-1/2(6-8x))=0



Domain of the equation: 5(5x-10)!=0

x∈R





Domain of the equation: 2(6-8x))!=0

x∈R



We add all the numbers together, and all the variables

5(x-3)-2/5(5x-10)-(-1/2(-8x+6))=0

We multiply parentheses

5x-2/5(5x-10)-(-1/2(-8x+6))-15=0

We calculate fractions


5x+(-4x(-)/(5(5x-10)*2(-8x+6)))+(-(-5x5)/(5(5x-10)*2(-8x+6)))-15=0



We calculate terms in parentheses: +(-4x(-)/(5(5x-10)*2(-8x+6))), so:

-4x(-)/(5(5x-10)*2(-8x+6))

We add all the numbers together, and all the variables

-4x0/(5(5x-10)*2(-8x+6))

We multiply all the terms by the denominator


-4x0

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)





We calculate terms in parentheses: +(-(-5x5)/(5(5x-10)*2(-8x+6))), so:

-(-5x5)/(5(5x-10)*2(-8x+6))

We add all the numbers together, and all the variables

-(-5x^5)/(5(5x-10)*2(-8x+6))

We multiply all the terms by the denominator


-(-5x^5)

We do not support expression: x^5

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