5(x-3)-1/2(5x-10)=-1/2(6-8x)

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Solution for 5(x-3)-1/2(5x-10)=-1/2(6-8x) equation: 



5(x-3)-1/2(5x-10)=-1/2(6-8x)

We move all terms to the left:

5(x-3)-1/2(5x-10)-(-1/2(6-8x))=0



Domain of the equation: 2(5x-10)!=0

x∈R





Domain of the equation: 2(6-8x))!=0

x∈R



We add all the numbers together, and all the variables

5(x-3)-1/2(5x-10)-(-1/2(-8x+6))=0

We multiply parentheses

5x-1/2(5x-10)-(-1/2(-8x+6))-15=0

We calculate fractions


5x+(-2x(-)/(2(5x-10)*2(-8x+6)))+(-(-2x5)/(2(5x-10)*2(-8x+6)))-15=0



We calculate terms in parentheses: +(-2x(-)/(2(5x-10)*2(-8x+6))), so:

-2x(-)/(2(5x-10)*2(-8x+6))

We add all the numbers together, and all the variables

-2x0/(2(5x-10)*2(-8x+6))

We multiply all the terms by the denominator


-2x0

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)





We calculate terms in parentheses: +(-(-2x5)/(2(5x-10)*2(-8x+6))), so:

-(-2x5)/(2(5x-10)*2(-8x+6))

We add all the numbers together, and all the variables

-(-2x^5)/(2(5x-10)*2(-8x+6))

We multiply all the terms by the denominator


-(-2x^5)

We do not support expression: x^5

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