5(x-3)+7x=6-(4x-5)

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Solution for 5(x-3)+7x=6-(4x-5) equation: 



5(x-3)+7x=6-(4x-5)

We move all terms to the left:

5(x-3)+7x-(6-(4x-5))=0

We add all the numbers together, and all the variables

7x+5(x-3)-(6-(4x-5))=0

We multiply parentheses

7x+5x-(6-(4x-5))-15=0



We calculate terms in parentheses: -(6-(4x-5)), so:

6-(4x-5)

determiningTheFunctionDomain
-(4x-5)+6

We get rid of parentheses

-4x+5+6

We add all the numbers together, and all the variables

-4x+11

Back to the equation:

-(-4x+11)



We add all the numbers together, and all the variables

12x-(-4x+11)-15=0

We get rid of parentheses

12x+4x-11-15=0

We add all the numbers together, and all the variables

16x-26=0

We move all terms containing x to the left, all other terms to the right

16x=26

x=26/16

x=1+5/8

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