5(x-3)+4x=6x+2(x-4)

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Solution for 5(x-3)+4x=6x+2(x-4) equation: 



5(x-3)+4x=6x+2(x-4)

We move all terms to the left:

5(x-3)+4x-(6x+2(x-4))=0

We add all the numbers together, and all the variables

4x+5(x-3)-(6x+2(x-4))=0

We multiply parentheses

4x+5x-(6x+2(x-4))-15=0



We calculate terms in parentheses: -(6x+2(x-4)), so:

6x+2(x-4)

We multiply parentheses

6x+2x-8

We add all the numbers together, and all the variables

8x-8

Back to the equation:

-(8x-8)



We add all the numbers together, and all the variables

9x-(8x-8)-15=0

We get rid of parentheses

9x-8x+8-15=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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