5(x-3)+4x=41

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Solution for 5(x-3)+4x=41 equation: 



5(x-3)+4x=41

We move all terms to the left:

5(x-3)+4x-(41)=0

We add all the numbers together, and all the variables

4x+5(x-3)-41=0

We multiply parentheses

4x+5x-15-41=0

We add all the numbers together, and all the variables

9x-56=0

We move all terms containing x to the left, all other terms to the right

9x=56

x=56/9

x=6+2/9

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