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5(x-3)+4x=3(3x-5)
We move all terms to the left:
5(x-3)+4x-(3(3x-5))=0
We add all the numbers together, and all the variables
4x+5(x-3)-(3(3x-5))=0
We multiply parentheses
4x+5x-(3(3x-5))-15=0
We calculate terms in parentheses: -(3(3x-5)), so:We add all the numbers together, and all the variables
3(3x-5)
We multiply parentheses
9x-15
Back to the equation:
-(9x-15)
9x-(9x-15)-15=0
We get rid of parentheses
9x-9x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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