5(x-3)+2=3(x-4)

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Solution for 5(x-3)+2=3(x-4) equation: 



5(x-3)+2=3(x-4)

We move all terms to the left:

5(x-3)+2-(3(x-4))=0

We multiply parentheses

5x-(3(x-4))-15+2=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

5x-(3x-12)-13=0

We get rid of parentheses

5x-3x+12-13=0

We add all the numbers together, and all the variables

2x-1=0

We move all terms containing x to the left, all other terms to the right

2x=1

x=1/2

x=1/2

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