5(x-3)+2=2(x-4)+2x-1

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Solution for 5(x-3)+2=2(x-4)+2x-1 equation: 



5(x-3)+2=2(x-4)+2x-1

We move all terms to the left:

5(x-3)+2-(2(x-4)+2x-1)=0

We multiply parentheses

5x-(2(x-4)+2x-1)-15+2=0



We calculate terms in parentheses: -(2(x-4)+2x-1), so:

2(x-4)+2x-1

We add all the numbers together, and all the variables

2x+2(x-4)-1

We multiply parentheses

2x+2x-8-1

We add all the numbers together, and all the variables

4x-9

Back to the equation:

-(4x-9)



We add all the numbers together, and all the variables

5x-(4x-9)-13=0

We get rid of parentheses

5x-4x+9-13=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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