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5(x-3)+2=2(2x-1)+1+3x
We move all terms to the left:
5(x-3)+2-(2(2x-1)+1+3x)=0
We multiply parentheses
5x-(2(2x-1)+1+3x)-15+2=0
We calculate terms in parentheses: -(2(2x-1)+1+3x), so:We add all the numbers together, and all the variables
2(2x-1)+1+3x
determiningTheFunctionDomain 2(2x-1)+3x+1
We add all the numbers together, and all the variables
3x+2(2x-1)+1
We multiply parentheses
3x+4x-2+1
We add all the numbers together, and all the variables
7x-1
Back to the equation:
-(7x-1)
5x-(7x-1)-13=0
We get rid of parentheses
5x-7x+1-13=0
We add all the numbers together, and all the variables
-2x-12=0
We move all terms containing x to the left, all other terms to the right
-2x=12
x=12/-2
x=-6
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