5(x-3)+2(x-4)=19

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Solution for 5(x-3)+2(x-4)=19 equation: 



5(x-3)+2(x-4)=19

We move all terms to the left:

5(x-3)+2(x-4)-(19)=0

We multiply parentheses

5x+2x-15-8-19=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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