5(x-3)+2(x+1)=2(x-2)

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Solution for 5(x-3)+2(x+1)=2(x-2) equation: 



5(x-3)+2(x+1)=2(x-2)

We move all terms to the left:

5(x-3)+2(x+1)-(2(x-2))=0

We multiply parentheses

5x+2x-(2(x-2))-15+2=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

7x-(2x-4)-13=0

We get rid of parentheses

7x-2x+4-13=0

We add all the numbers together, and all the variables

5x-9=0

We move all terms containing x to the left, all other terms to the right

5x=9

x=9/5

x=1+4/5

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