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5(x-3)+15=2(3x-4)
We move all terms to the left:
5(x-3)+15-(2(3x-4))=0
We multiply parentheses
5x-(2(3x-4))-15+15=0
We calculate terms in parentheses: -(2(3x-4)), so:We add all the numbers together, and all the variables
2(3x-4)
We multiply parentheses
6x-8
Back to the equation:
-(6x-8)
5x-(6x-8)=0
We get rid of parentheses
5x-6x+8=0
We add all the numbers together, and all the variables
-1x+8=0
We move all terms containing x to the left, all other terms to the right
-x=-8
x=-8/-1
x=+8
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