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5(x-2)=6x-2(x+3)
We move all terms to the left:
5(x-2)-(6x-2(x+3))=0
We multiply parentheses
5x-(6x-2(x+3))-10=0
We calculate terms in parentheses: -(6x-2(x+3)), so:We get rid of parentheses
6x-2(x+3)
We multiply parentheses
6x-2x-6
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
5x-4x+6-10=0
We add all the numbers together, and all the variables
x-4=0
We move all terms containing x to the left, all other terms to the right
x=4
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