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5(x-2)=6(x+2)-x
We move all terms to the left:
5(x-2)-(6(x+2)-x)=0
We multiply parentheses
5x-(6(x+2)-x)-10=0
We calculate terms in parentheses: -(6(x+2)-x), so:We get rid of parentheses
6(x+2)-x
We add all the numbers together, and all the variables
-1x+6(x+2)
We multiply parentheses
-1x+6x+12
We add all the numbers together, and all the variables
5x+12
Back to the equation:
-(5x+12)
5x-5x-12-10=0
We add all the numbers together, and all the variables
-22!=0
There is no solution for this equation
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