5(x-2)=4(x-3)+(x-3)

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Solution for 5(x-2)=4(x-3)+(x-3) equation:


Simplifying
5(x + -2) = 4(x + -3) + (x + -3)

Reorder the terms:
5(-2 + x) = 4(x + -3) + (x + -3)
(-2 * 5 + x * 5) = 4(x + -3) + (x + -3)
(-10 + 5x) = 4(x + -3) + (x + -3)

Reorder the terms:
-10 + 5x = 4(-3 + x) + (x + -3)
-10 + 5x = (-3 * 4 + x * 4) + (x + -3)
-10 + 5x = (-12 + 4x) + (x + -3)

Reorder the terms:
-10 + 5x = -12 + 4x + (-3 + x)

Remove parenthesis around (-3 + x)
-10 + 5x = -12 + 4x + -3 + x

Reorder the terms:
-10 + 5x = -12 + -3 + 4x + x

Combine like terms: -12 + -3 = -15
-10 + 5x = -15 + 4x + x

Combine like terms: 4x + x = 5x
-10 + 5x = -15 + 5x

Add '-5x' to each side of the equation.
-10 + 5x + -5x = -15 + 5x + -5x

Combine like terms: 5x + -5x = 0
-10 + 0 = -15 + 5x + -5x
-10 = -15 + 5x + -5x

Combine like terms: 5x + -5x = 0
-10 = -15 + 0
-10 = -15

Solving
-10 = -15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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