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5(x-2)=3(x-4)+2
We move all terms to the left:
5(x-2)-(3(x-4)+2)=0
We multiply parentheses
5x-(3(x-4)+2)-10=0
We calculate terms in parentheses: -(3(x-4)+2), so:We get rid of parentheses
3(x-4)+2
We multiply parentheses
3x-12+2
We add all the numbers together, and all the variables
3x-10
Back to the equation:
-(3x-10)
5x-3x+10-10=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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