5(x-2)=11(x-3)-7

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Solution for 5(x-2)=11(x-3)-7 equation: 



5(x-2)=11(x-3)-7

We move all terms to the left:

5(x-2)-(11(x-3)-7)=0

We multiply parentheses

5x-(11(x-3)-7)-10=0



We calculate terms in parentheses: -(11(x-3)-7), so:

11(x-3)-7

We multiply parentheses

11x-33-7

We add all the numbers together, and all the variables

11x-40

Back to the equation:

-(11x-40)



We get rid of parentheses

5x-11x+40-10=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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