5(x-2)=-2(10-x)+4x

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Solution for 5(x-2)=-2(10-x)+4x equation: 



5(x-2)=-2(10-x)+4x

We move all terms to the left:

5(x-2)-(-2(10-x)+4x)=0

We add all the numbers together, and all the variables

5(x-2)-(-2(-1x+10)+4x)=0

We multiply parentheses

5x-(-2(-1x+10)+4x)-10=0



We calculate terms in parentheses: -(-2(-1x+10)+4x), so:

-2(-1x+10)+4x

We add all the numbers together, and all the variables

4x-2(-1x+10)

We multiply parentheses

4x+2x-20

We add all the numbers together, and all the variables

6x-20

Back to the equation:

-(6x-20)



We get rid of parentheses

5x-6x+20-10=0

We add all the numbers together, and all the variables

-1x+10=0

We move all terms containing x to the left, all other terms to the right

-x=-10

x=-10/-1

x=+10

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