5(x-2)-2(4x-3)-(x+4)=8

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Solution for 5(x-2)-2(4x-3)-(x+4)=8 equation: 



5(x-2)-2(4x-3)-(x+4)=8

We move all terms to the left:

5(x-2)-2(4x-3)-(x+4)-(8)=0

We multiply parentheses

5x-8x-(x+4)-10+6-8=0

We get rid of parentheses

5x-8x-x-4-10+6-8=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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