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5(x-2)-1=2(x+2)
We move all terms to the left:
5(x-2)-1-(2(x+2))=0
We multiply parentheses
5x-(2(x+2))-10-1=0
We calculate terms in parentheses: -(2(x+2)), so:We add all the numbers together, and all the variables
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
5x-(2x+4)-11=0
We get rid of parentheses
5x-2x-4-11=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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