5(x-2)+x=6(x+3)-4x=

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Solution for 5(x-2)+x=6(x+3)-4x= equation: 



5(x-2)+x=6(x+3)-4x=

We move all terms to the left:

5(x-2)+x-(6(x+3)-4x)=0

We add all the numbers together, and all the variables

x+5(x-2)-(6(x+3)-4x)=0

We multiply parentheses

x+5x-(6(x+3)-4x)-10=0



We calculate terms in parentheses: -(6(x+3)-4x), so:

6(x+3)-4x

We add all the numbers together, and all the variables

-4x+6(x+3)

We multiply parentheses

-4x+6x+18

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

6x-(2x+18)-10=0

We get rid of parentheses

6x-2x-18-10=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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