5(x-2)+x=6(x+3)-)-4x

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Solution for 5(x-2)+x=6(x+3)-)-4x equation: 



5(x-2)+x=6(x+3)-)-4x

We move all terms to the left:

5(x-2)+x-(6(x+3)-)-4x)=0

We add all the numbers together, and all the variables

x+5(x-2)-(6(x+3)-)-4x)=0

We multiply parentheses

x+5x-(6(x+3)-)-4x)-10=0



We calculate terms in parentheses: -(6(x+3)-), so:

6(x+3)-

We add all the numbers together, and all the variables

6(x+3)

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We add all the numbers together, and all the variables

6x-(6x+18)-4x)-10=0

We get rid of parentheses

6x-6x-4x)-10-18=0

We add all the numbers together, and all the variables

-4x)-10-18=0

x=0/1

x=0

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