5(x-2)+6=x(x+4)

Solution for 5(x-2)+6=x(x+4) equation:

5(x-2)+6=x(x+4)

We move all terms to the left:

5(x-2)+6-(x(x+4))=0

We multiply parentheses

5x-(x(x+4))-10+6=0


We calculate terms in parentheses: -(x(x+4)), so:

x(x+4)

We multiply parentheses

x^2+4x

Back to the equation:

-(x^2+4x)


We add all the numbers together, and all the variables

5x-(x^2+4x)-4=0

We get rid of parentheses

-x^2+5x-4x-4=0

We add all the numbers together, and all the variables

-1x^2+x-4=0

a = -1; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-1)·(-4)
Δ = -15
Delta is less than zero, so there is no solution for the equation