5(x-2)+4x=8(x+1)-9x

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Solution for 5(x-2)+4x=8(x+1)-9x equation: 



5(x-2)+4x=8(x+1)-9x

We move all terms to the left:

5(x-2)+4x-(8(x+1)-9x)=0

We add all the numbers together, and all the variables

4x+5(x-2)-(8(x+1)-9x)=0

We multiply parentheses

4x+5x-(8(x+1)-9x)-10=0



We calculate terms in parentheses: -(8(x+1)-9x), so:

8(x+1)-9x

We add all the numbers together, and all the variables

-9x+8(x+1)

We multiply parentheses

-9x+8x+8

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We add all the numbers together, and all the variables

9x-(-1x+8)-10=0

We get rid of parentheses

9x+1x-8-10=0

We add all the numbers together, and all the variables

10x-18=0

We move all terms containing x to the left, all other terms to the right

10x=18

x=18/10

x=1+4/5

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