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5(x-2)+4x=2+3(x-8)
We move all terms to the left:
5(x-2)+4x-(2+3(x-8))=0
We add all the numbers together, and all the variables
4x+5(x-2)-(2+3(x-8))=0
We multiply parentheses
4x+5x-(2+3(x-8))-10=0
We calculate terms in parentheses: -(2+3(x-8)), so:We add all the numbers together, and all the variables
2+3(x-8)
determiningTheFunctionDomain 3(x-8)+2
We multiply parentheses
3x-24+2
We add all the numbers together, and all the variables
3x-22
Back to the equation:
-(3x-22)
9x-(3x-22)-10=0
We get rid of parentheses
9x-3x+22-10=0
We add all the numbers together, and all the variables
6x+12=0
We move all terms containing x to the left, all other terms to the right
6x=-12
x=-12/6
x=-2
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