5(x-2)+4=10(x-1)-6

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Solution for 5(x-2)+4=10(x-1)-6 equation: 



5(x-2)+4=10(x-1)-6

We move all terms to the left:

5(x-2)+4-(10(x-1)-6)=0

We multiply parentheses

5x-(10(x-1)-6)-10+4=0



We calculate terms in parentheses: -(10(x-1)-6), so:

10(x-1)-6

We multiply parentheses

10x-10-6

We add all the numbers together, and all the variables

10x-16

Back to the equation:

-(10x-16)



We add all the numbers together, and all the variables

5x-(10x-16)-6=0

We get rid of parentheses

5x-10x+16-6=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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