5(x-2)+3(x+4)=6(x-4)+12

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Solution for 5(x-2)+3(x+4)=6(x-4)+12 equation:



5(x-2)+3(x+4)=6(x-4)+12
We move all terms to the left:
5(x-2)+3(x+4)-(6(x-4)+12)=0
We multiply parentheses
5x+3x-(6(x-4)+12)-10+12=0
We calculate terms in parentheses: -(6(x-4)+12), so:
6(x-4)+12
We multiply parentheses
6x-24+12
We add all the numbers together, and all the variables
6x-12
Back to the equation:
-(6x-12)
We add all the numbers together, and all the variables
8x-(6x-12)+2=0
We get rid of parentheses
8x-6x+12+2=0
We add all the numbers together, and all the variables
2x+14=0
We move all terms containing x to the left, all other terms to the right
2x=-14
x=-14/2
x=-7

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