5(x-2)+2x=15-2(x-1)

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Solution for 5(x-2)+2x=15-2(x-1) equation: 



5(x-2)+2x=15-2(x-1)

We move all terms to the left:

5(x-2)+2x-(15-2(x-1))=0

We add all the numbers together, and all the variables

2x+5(x-2)-(15-2(x-1))=0

We multiply parentheses

2x+5x-(15-2(x-1))-10=0



We calculate terms in parentheses: -(15-2(x-1)), so:

15-2(x-1)

determiningTheFunctionDomain
-2(x-1)+15

We multiply parentheses

-2x+2+15

We add all the numbers together, and all the variables

-2x+17

Back to the equation:

-(-2x+17)



We add all the numbers together, and all the variables

7x-(-2x+17)-10=0

We get rid of parentheses

7x+2x-17-10=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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