5(x-2)+(2-5x)=4-2(2-3x)-3x

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Solution for 5(x-2)+(2-5x)=4-2(2-3x)-3x equation: 



5(x-2)+(2-5x)=4-2(2-3x)-3x

We move all terms to the left:

5(x-2)+(2-5x)-(4-2(2-3x)-3x)=0

We add all the numbers together, and all the variables

5(x-2)+(-5x+2)-(4-2(-3x+2)-3x)=0

We multiply parentheses

5x+(-5x+2)-(4-2(-3x+2)-3x)-10=0

We get rid of parentheses

5x-5x-(4-2(-3x+2)-3x)+2-10=0



We calculate terms in parentheses: -(4-2(-3x+2)-3x), so:

4-2(-3x+2)-3x

determiningTheFunctionDomain
-2(-3x+2)-3x+4

We add all the numbers together, and all the variables

-3x-2(-3x+2)+4

We multiply parentheses

-3x+6x-4+4

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

-3x-8=0

We move all terms containing x to the left, all other terms to the right

-3x=8

x=8/-3

x=-2+2/3

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