If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5(x-2)(x+3)+2(x-3)(x+2)-3(x+2)(x+3)=0
We multiply parentheses ..
5(+x^2+3x-2x-6)+2(x-3)(x+2)-3(x+2)(x+3)=0
We multiply parentheses
5x^2+15x-10x+2(x-3)(x+2)-3(x+2)(x+3)-30=0
We multiply parentheses ..
5x^2+2(+x^2+2x-3x-6)+15x-10x-3(x+2)(x+3)-30=0
We add all the numbers together, and all the variables
5x^2+2(+x^2+2x-3x-6)+5x-3(x+2)(x+3)-30=0
We multiply parentheses
5x^2+2x^2+4x-6x+5x-3(x+2)(x+3)-12-30=0
We multiply parentheses ..
5x^2+2x^2-3(+x^2+3x+2x+6)+4x-6x+5x-12-30=0
We add all the numbers together, and all the variables
7x^2-3(+x^2+3x+2x+6)+3x-42=0
We multiply parentheses
7x^2-3x^2-9x-6x+3x-18-42=0
We add all the numbers together, and all the variables
4x^2-12x-60=0
a = 4; b = -12; c = -60;
Δ = b2-4ac
Δ = -122-4·4·(-60)
Δ = 1104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1104}=\sqrt{16*69}=\sqrt{16}*\sqrt{69}=4\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{69}}{2*4}=\frac{12-4\sqrt{69}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{69}}{2*4}=\frac{12+4\sqrt{69}}{8} $
| -.75x=-3+3x | | m^2+4m+16=0 | | 2/7+m=5/7 | | 27+m=57 | | 2(10+y)+y=80 | | m/9+55=63 | | 8r-26=46 | | 5(j-92)=30 | | 75=5(u-74) | | b/3+12=14 | | d-57/3=8 | | |m+1|+5=34 | | 4(r+16)=80 | | X^2+20x-16=-1 | | 16+3z=6+4z | | 4v+13=–15 | | −7a+14=35 | | 6-10x=-8 | | ⅖y=-2 | | 2x+3=(3+2x)+6 | | 3/12x=12 | | 9^x-12.3^x+27=0 | | 148=n^2+2 | | 28+7x=119 | | 980=1.03x | | 0.36=0.5(x^2) | | 2x+8(x−8)=2(x−16) | | 16x-8x=8-5 | | -12-16=x-6 | | 12=-2.8t+51 | | 0.13(2x×8)=0.06x-3 | | x=14.62 |