5(x-11)+13(x-2)=4x-2(3-x)

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Solution for 5(x-11)+13(x-2)=4x-2(3-x) equation: 



5(x-11)+13(x-2)=4x-2(3-x)

We move all terms to the left:

5(x-11)+13(x-2)-(4x-2(3-x))=0

We add all the numbers together, and all the variables

5(x-11)+13(x-2)-(4x-2(-1x+3))=0

We multiply parentheses

5x+13x-(4x-2(-1x+3))-55-26=0



We calculate terms in parentheses: -(4x-2(-1x+3)), so:

4x-2(-1x+3)

We multiply parentheses

4x+2x-6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We add all the numbers together, and all the variables

18x-(6x-6)-81=0

We get rid of parentheses

18x-6x+6-81=0

We add all the numbers together, and all the variables

12x-75=0

We move all terms containing x to the left, all other terms to the right

12x=75

x=75/12

x=6+1/4

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